Matematika Sekolah Dasar Q.Tingkat kesulitan : sangat sulitMateri : DeretCarilah jumlah deret geometris tak terhingga :[tex]1 + \frac{1}{ {2}^{2} } + \frac{1}{2^{4} } + ....[/tex][tex]6 - 2 + \frac{2}{3} - .......[/tex]​

melanyemmerichulv – March 05, 2023

Q.
Tingkat kesulitan : sangat sulit
Materi : Deret

Carilah jumlah deret geometris tak terhingga :
[tex]1 + \frac{1}{ {2}^{2} } + \frac{1}{2^{4} } + ....[/tex]
[tex]6 - 2 + \frac{2}{3} - .......[/tex]
​

1 + 1/2² + 1/2⁴

r = 1/2² ÷ 1 = ¼

a = 1

[tex] \\ [/tex]

S inf = a/1-r

S inf = 1/1-¼

S inf = 1/¾

S inf = 1 × 4/3

S inf = 4/3

[tex] \\ [/tex]

6 - 2 + ⅔

r = -2 ÷ 6 = -⅓

a = 6

S inf = a/1-r

S inf = 6/1-(-⅓)

S inf = 6/4/3

S inf = 6 × 3/4

S inf = 3 × 3/2

S inf = 9/2

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